FIGUERA'S AETHER MAGNETIC FIELDS LINEAR PUMP, REVIVED

[Ufopolitics]

Hello All,

This post is about the way that I will make the future tests by using the existing Fifteen (15) Sequential Coils that I have already built.
Fifteen (15) Coils are Divisible by Three (3).
Each one of these Sequential Coils have 6.25 Ohms Resistance.

However, I will be making TWO TESTS:

1: THE SYMMETRIC TEST

• The Symmetric Test, where the Division would be done by Grouping Five (5) Coils (5-5-5)
• Each Group of Five Coils in SERIES.
• Where All Three Groups will have the same Total Resistance of 31.25 Ohms Each.
• However, the Voltages would NOT be distributed Equally.
• The Center Coil Q3 will receive around HALF of the Resistance Value, or 15 Volts.
• This Relationship of V/R would generate a Current of 0.5 Amp.
• While the Coils Q1 & Q2 (of same Resistance as Q3) would be powered by around the SAME Voltage, or 31 Volts
• These relationship of V/R on Q1 & Q2 would generate a Current of around 1.0 Amp.
• Except, whenever there would be a Transition (Tx).
• Which for the Q1 & Q2 will LOWER Resistance to 15.625 Ohms.
• On these Q1 & Q2 Transitions, the Currents will increase to approximately 2.0 Amps (31.25V/15.625 Ohms)

2: THE ASYMMETRIC TEST

• The Asymmetric Test, where the Division would be done by Grouping Q1 & Q2 with SIX (6) Coils.
• While Q3 would be only THREE (3) Coils
• As ALL Three Groups would also be connected in SERIES between their Internal Configuring Coils.
• Where All Three Groups will have DIFFERENT Resistances.
• Q1 & Q2 would have 37.5 Ohms
• While Q3 would only have 18.75 Ohms
• And also (as previous test), the Voltages would NOT be distributed Equally.
• The Center Coil Q3 will receive around HALF of the Resistance Value, or 9 Volts.
• This Relationship of V/R would generate a Current of around 0.5 Amp.
• While the Coils Q1 & Q2 would be powered by around the SAME Voltage as their Resistance Values, or 37.5 Volts
• These relationship of V/R on Q1 & Q2 would generate a Current of around 1.0 Amp.
• Except, whenever there would be a Transition (Tx) (Parallel Connection of Q1 & Q2)
• Which for the Q1 & Q2 will LOWER Resistance to 18.75 Ohms.
• On these Q1 & Q2 Transitions, the Currents will increase to approximately 2.0 Amps (37.5V/15.625 Ohms)

These Two Tests will basically play with the Field Spatial Volume differences, between the Three Coils.
Because I would try to keep currents around the same values for BOTH Tests.
Where Q1 & Q2 would have around 1.0 Amp, whenever powered for the Two Tests
And Q3 around 0.5 Amp.
As for BOTH Tests, the Transition Currents would increase EXACTLY at 2.0 Amps.

RESUMING: I will use the TWO SEPARATED Voltage SUPPLY UNITS as the 'Voltage Regulator' to keep these currents identical for BOTH Tests.
Because, as I mentioned before, Q1 & Q2 would be powered by a SEPARATED PSU than Q3 for BOTH Tests.
These Two Tests will give us -based on their OUTPUT results- which one will cause a greater and more robust INDUCTION on the Main Secondary. (I still have not made FC1 & FC2)

Regards to All

Ufopolitics

EDIT 1:  For BOTH Tests, the Mechanical Commutator Driver would be wired for Four Full Cycles per Revolution, therefore, to reach the 60 Hertz, it will just need to spin at 900 RPM's.

[Ufopolitics]

Hello All,

Yesterday and this morning (7/12/2026) our Servers went through an Upgrade of the OS.
It took place from 12:00 AM to 6:00AM Eastern USA time, which generated an Outage of ALL our websites for the time it took.

It was my mistake not to read the message they sent me with previous notice, as I would have posted here before it took place.

I apologize for the Outage.

Now everything should be running fine.

Regards

Ufopolitics

[Ufopolitics]

Hello All,

Ok, I just wanted to "clarify" something about these future tests on only Three Sequential Coils:

• At ANY POINT IN TIME, I am giving up on my Original Setup of 15 Coils, 8 Groups and the Bipolar 32 Elements Commutator.
• These are just FIELD REDUCED RESOLUTION TESTS to its Minimal Step Displacement.
• It is done in order that MANY BUILDERS here could also be able to REPLICATE them (on the event that results are clearly demonstrated to be POSITIVE)
• As to observe the GENERATED OUTPUT AC SINEWAVE for such REDUCED STEPS.

HOWEVER, I am very clear about Field behavior on a Higher Field Resolution with HIGHER number of STEPS.
I Just wanted to make these tests about a reduced environment, fewer steps of the Exciting Field and their output results, along with the resulting AC Sinewave.

On the event that these Tests do NOT WORK, then I will post it here, as I would proceed with the Bipolar Dual Commutator Driver and the FULL EIGHT STEPS of EIGHT GROUPS.

As these tests would teach us all, if a Minimalist Field Setup works or not...


Regards to All

Ufopolitics

[kampen]

Reply to Ufopolitics Message #895: Way of Testing the 15 Coils

@ All,

This is a useful development because Ufopolitics is now proposing a controlled A/B experiment where the intended currents are kept approximately constant while the spatial distribution of the excitation coils changes.
That makes the comparison much more meaningful.

There is, however, one numerical error in his Asymmetric Test that should be corrected.

Check of his calculations:

Test	Group	Resistance	Voltage	Calculated current	Verdict
Symmetric 5-5-5	Q1/Q2	31.25 Ω	31 V	0.992 A	✓
Symmetric	Q3	31.25 Ω	15 V	0.480 A	✓
Symmetric transition	Q1 ∥ Q2	15.625 Ω	31.25 V	2.00 A total	✓
Asymmetric 6-3-6	Q1/Q2	37.5 Ω	37.5 V	1.00 A	✓
Asymmetric	Q3	18.75 Ω	9 V	0.480 A	✓
Asymmetric transition	Q1 ∥ Q2	18.75 Ω	37.5 V	2.00 A total	✓

The error is in this sentence:
"2.0 Amps (37.5V/15.625 Ohms)"
For the 6-3-6 configuration, two 37.5 Ω groups in parallel give:
37.5 Ω ∥ 37.5 Ω = 18.75 Ω
and therefore:
37.5 V / 18.75 Ω = 2.0 A
So his stated 2 A result is correct, but the denominator 15.625 Ω is a copy-over from the symmetric 5-5-5 test.

His 900-RPM calculation is also correct provided the commutator genuinely produces four complete electrical cycles per mechanical revolution:
60 cycles/s ÷ 4 cycles/revolution = 15 revolutions/s = 900 RPM.

What I particularly like about this experiment:
The comparison isolates something useful:
Symmetric:
 5 – 5 – 5
versus
Asymmetric:
 6 – 3 – 6
while attempting to maintain approximately:
Q1/Q2 ≈ 1.0 A
 Q3 ≈ 0.5 A
 transition total ≈ 2.0 A

Consequently, if the Main Secondary output changes significantly between the two configurations, coil geometry/spatial excitation becomes a plausible variable to investigate further rather than simply attributing the difference to a different nominal drive current.

There is one caveat: equal current does NOT mean equal magnetic excitation.
Six series coils at 1 A have 20% more ampere-turns than five identical coils at 1 A.
The 3-coil Q3 group also has only 60% of the turns of the 5-coil Q3 group.

Therefore, the Asymmetric experiment deliberately changes both spatial geometry and ampere-turn distribution.
That is fine, but the results should be described accordingly.

One other important measurement point:
I would not assume that the transition current actually becomes exactly 2.0 A just from the DC resistance calculation.
These are inductive coils being commutated.

During the transition, instantaneous current depends on inductance, magnetic coupling, switching time, back-EMF, core state, and commutator timing. 
The 2 A is the resistive steady-state prediction.

So during the actual experiment, I ask Ufopolitics to measure the Q1/Q2 current waveform with the scope, particularly around Tx.

That will tell us whether the real transition peak is 2 A, lower, or potentially higher due to a transient.

Overall, I think 5-5-5 versus 6-3-6 is a much stronger comparative experiment than testing only one configuration.
If the same Main Secondary, core, RPM/frequency, measurement instruments, and output load are retained, the result should provide useful information about whether his proposed asymmetric field geometry offers an advantage.

Kind regards, Alex / @kampen

[kampen]

@ All, 

I have put together the attached diagram for a comparative test using the same 15 coils and the same hardware, but with two different coil groupings:

• Test 1 – Symmetrical: 5–5–5 coils
   Q1 = 31.25 Ω, Q3 = 31.25 Ω, Q2 = 31.25 Ω
• Test 2 – Asymmetrical: 6–3–6 coils
   Q1 = 37.5 Ω, Q3 = 18.75 Ω, Q2 = 37.5 Ω

Each individual coil is 6.25 Ω.

The purpose of the test is to compare the two configurations under controlled conditions while keeping the mechanical setup, coils, commutator, secondary winding, RPM, and measurement method the same.

Q1 and Q2 are alternately switched by the mechanical commutator, while Q3 is supplied separately and remains continuously energized. 

The target operating point is approximately 1 A for Q1/Q2 and 0.5 A for Q3
with the commutator running at 900 RPM, corresponding to approximately 60 Hz electrical output with four electrical cycles per revolution.

For both tests, plan to record:

• Q1, Q2 and Q3 current
• Output Voltage
• Output frequency and waveform
• Output power into a known resistive load
• Input conditions for each configuration

The main point is to make this a comparison and see what measurable difference, if any, results purely from changing the coil distribution from 5–5–5 to 6–3–6.

I have tried to show all wiring, intended operating points, transition conditions, measurement points, and the test procedure in the diagram.

Appreciate any feedback before running the tests, especially if anyone spots a wiring issue, measurement problem, or another parameter that should be recorded so the comparison is as fair and useful as possible.

Kind regards, Alex / @ kampen